Fiisigiska carruurta: iska caabiyeyaasha taxanaha ah iyo barbar socda

Cabceyaasha taxanaha >

Marka resistors-ku ku xidhmaan dhammaadka-ilaa-dhamaadka wareegga wareegga (sida sawirka ka muuqata). hoos) waxaa la sheegay in ay ku jiraan "taxane." Si aad u hesho caabbinta guud ee iska caabbinta ee taxana ah waxaad kaliya ku darsataa qiimaha resistor kasta. Tusaalaha hoose wadarta iska caabintu waxay noqonaysaa R1 + R2.

Halkan waa tusaale kale oo ka mid ah tiro iska caabin ah oo taxane ah. Wadarta qiimaha iska caabbinta guud ahaan danab V waa R1 + R2 + R3 + R4 + R5.

> Dhibaatada tusaale: 6

Isticmaalka jaantuska wareegga hoose, xalliso qiimaha iska caabbinta maqan R.

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Marka hore waxaan qiyaas caabbinta u dhiganta ee wareegga oo dhan. Laga soo bilaabo sharciga Ohm waxaan ognahay in iska caabin = Voltage / hadda, sidaas darteed

Resistance = 50volts / 2amps

Resistance = 5 + 3 + 4 + 7 + R

Resistance = 19 +R

Hadda waxaanu ku xidhnay 25 iska caabin waxaanu helnaa

25 = 19 + R

R = 6 ohms

Parallel Resistors >

Isku-barbar-ku-dhigeyaasha waa iska-caabiyeyaasha ku xidhan midba midka kale ee wareegga korantada. Hoos ka daawo sawirka Sawirkan R1, R2, iyo R3 ayaa dhamaantood isku xidhan si is barbar socda.

Markaan xisaabinay iska caabinta taxanaha ah, waxaanu isu geynay iska caabin kasta si aanu u helno qiimaha. Tani waxay macno samaynaysaa sababtoo ah hadda ee korantada guud ahaan resistors waxay si siman ugu socon doontaa caabiyaha kasta. Marka resistors-ku ay isbarbar socdaan taasi maahan. Qaar ka mid ah kuwa hadda socda waxay mari doonaan R1, qaar waxay sii maraan R2, qaarna waxay sii maraan R3. resistor kastaa waxa uu bixiyaa wado dheeri ah oo uu hada ku safro

Waxaad arki kartaa in is-dhaafsiga wadarta iska caabinta ay tahay wadarta is-dhaafsiga iska caabin kasta oo is barbar socda. 4>Waa maxay iska caabin wadarta "R" guud ahaan danab V ee wareegga hoose?

Jawaab:

1/R = 5/20 + 4/20 + 1/20

1/R = 10/20 = ½

R = 2 Ohms

Ogsoonow in wadarta iska caabbinta ay ka yar tahay mid kasta oo ka mid ah resistors marka la barbar dhigo. Tani waxay noqon doontaamar walba xaalku ha ahaado. Iska caabin u dhigma ayaa had iyo jeer ka yaraan doona iska caabinta ugu yar marka la barbar dhigo.

Series and Parallel

Maxaad samaynaysaa marka aad leedahay wareeg ah oo leh iska caabin isku mid ah iyo kuwo taxane ah labadaba. ?

Fikirka lagu xallinayo wareegyada noocaan ah waa in qaybo yaryar oo wareeg ah loo kala qaybiyo qaybo is barbar socda. Marka hore samee qaybo kasta oo leh oo kaliya iska caabin taxane ah. Ka dibna ku beddel kuwa leh caabbinta u dhiganta. Marka xigta xalli qaybaha isbarbar socda. Hadda ku beddel kuwa iska caabiyeyaasha u dhigma. Sii wad tillaabooyinkan ilaa aad ka gaadhayso xalka

> > Tusaale mushkiladda: >>

Xal u yeelo iska caabbinta u dhiganta ee koronta V ee wareegga korantada Hoos:

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Waxaan ku aragnaa dhanka midig in wadarta iska caabbinta 6 iyo resistor 12 ay hadda isbarbar socdaan. Waxaan u xallin karnaa kuwan iska-caabiyeyaasha isbar-bar-dhigga ah si aan u helno caabbinta u dhiganta 4.

1/R = 1/6 + 1/12

1/R = 2/12 + 1/12

1/R = 3/12 = ¼

R = 4

Jaantuska wareegga cusub ayaa lagu muujiyay hoos.

Xirdigan waxaan ku xalineynaa resistors-ka taxanaha ah 4 iyo 11 si aan u helno 4 + 11 = 15. Hadda waxaan haysanaa laba resistors oo isbarbar socda, 15 iyo 10.

1/R = 1/15 + 1/10

1/R = 2/30 + 3/30

1/R = 5/30 = 1/6

R= 6

Cabbir u dhigma oo ka dhan ah V waa 6 ohms.

Hawlaha >

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Hordhaca Korontada

Korantada Wareegyada

Korantada Hadda

Sharciga Ohm

Caabiyeyaasha, Capacitors, iyo Inductors

Kormeerayaasha iyo Dahaarka

Electronics Dijital

Korantada Kale > 23>

Aasaaska Korontada

Isgaadhsiinta Elektarooniga ah

Isticmaalka Korontada

Glossary of Electricity Terms

Sayniska >> Fiisigiska carruurta